Tough math problems, I guess...





Click here to go to the NEW College Discussion Forum

Discus: What Are My Chances?: February 2003 Archive: Tough math problems, I guess...
By Weidamengxing (Weidamengxing) on Thursday, January 30, 2003 - 12:09 pm: Edit

Thanks, everyone.

1.Let G be an Abelian group with identity e and let n be some fixed integer. Prove that the set of all elements of G that satisfy the equation X^n = e is a subgroup of G. Give an example of a group G in which the set of all elements of G taht satisfy the equation X^2 = e does not form a subgroup of G.

2. Prove that an Abelian group with two elemtns of order 2 (dude, does that include the identity? I don't understand.) must have a subgroup of order 4.

3. U(14)="<5>"="<3>". (Now, I can demostrate that is true, but how to prove it, by claiming each group is a subgroup of the other? And why"<3>" ="<5>" with both order of 5?)

By asdf on Thursday, January 30, 2003 - 12:56 pm: Edit

bump

By uk on Thursday, January 30, 2003 - 06:19 pm: Edit

what does "bump" even mean?/??

By incognito on Thursday, January 30, 2003 - 06:23 pm: Edit

it moves the message up to the top of the forum list so ppl can see it....i think

By uk on Thursday, January 30, 2003 - 06:34 pm: Edit

ok, so bump again

By asdf on Thursday, January 30, 2003 - 06:47 pm: Edit

Gah! I hate proofs!

By wdmx on Thursday, January 30, 2003 - 08:54 pm: Edit

nobody?? come on...

By io on Thursday, January 30, 2003 - 09:04 pm: Edit

bump, even though it ruins the quality

By io on Thursday, January 30, 2003 - 09:22 pm: Edit

jezzz, can't believe this...bump again

By meryl on Thursday, January 30, 2003 - 09:23 pm: Edit

hmm...looks like our friend jonh LOSS here didnt get an 800 on his SATs

By weidamengxing on Thursday, January 30, 2003 - 10:03 pm: Edit

any one can post something serious???!! don't ruin the saintity of math, please

By jony on Thursday, January 30, 2003 - 10:03 pm: Edit

hey meryl tanks fo me last post i am wetaded.

By john on Thursday, January 30, 2003 - 10:05 pm: Edit

the answer to the math question is: meryl has a 1.76cm dick.

By meryl on Thursday, January 30, 2003 - 10:13 pm: Edit

...or is it john has a 1.76 IQ....

By bumo on Tuesday, February 04, 2003 - 02:05 pm: Edit

bump

By Lurker on Tuesday, February 04, 2003 - 04:30 pm: Edit

BUMP = Bring Up My Post

btw, this is not a bump

By AzN_Cowboy on Tuesday, February 04, 2003 - 06:15 pm: Edit

The toughest math problems aren't the ones that just sound advanced.


Report an offensive message on this page    E-mail this page to a friend
Posting is currently disabled in this topic. Contact your discussion moderator for more information.

Administrator's Control Panel -- Board Moderators Only
Administer Page