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That was so much easier than that insane piece of crap they administered in June.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:36 am: Edit

oh really? I didn't take the june test but i thought the test today was REEEEEEEALY easy. it might have been cuz i studied, but i thought i ATE that test.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:37 am: Edit

i have some of the last answers:
47. 840
48. k = 2
49. 1 second
50. choice e, II and III only
and i didnt get #39 which was that weird matrix question...

By Shaman88 (Shaman88) on Saturday, October 09, 2004 - 10:42 am: Edit

The weird matrix question was 5 X 4 because in order for C = 2 X 4 and A = 2 X 5, there must be a 5 in the rows. Therefore, (2 X 5)(5 X 4) = (2 X 4).

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:43 am: Edit

aw damn it. i was gonna guess that but then i decided to not take the risk. hopefully i got most of the other questions right though...

how do your last few answers compare with mine?

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:45 am: Edit

hey so how did you do on the june test?

... looks like most people arn't done w/ the test yet

By Shaman88 (Shaman88) on Saturday, October 09, 2004 - 10:45 am: Edit

Oh yeah, what was the answer to that one problem with the intensity that varies inversely?

By Pennhomie33 (Pennhomie33) on Saturday, October 09, 2004 - 10:47 am: Edit

ahhhhhhhhhhhhh wang, hey man. i took ic today, lol

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:48 am: Edit

oooh um... damn it i forgot. but i know its I(intensity) times distance^2 = constant.
you plug, get the constant, then replug and solve for teh intensity. forgot teh exact numbers though

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:49 am: Edit

OMG WAIT I REMEMBER!!
it was 150*3^2 which = 1350
so then, I * 12^2 = 1350,
I = about 9.4

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 10:50 am: Edit

omg whos pennhomie!??! uh... i know its not vasant or ankit? um...jeremey?

By Shaman88 (Shaman88) on Saturday, October 09, 2004 - 10:51 am: Edit

Yeeah! I got that!

By Shaman88 (Shaman88) on Saturday, October 09, 2004 - 10:52 am: Edit

That absolute value of x one was just a reflection of the right side of the graph over the Y-Axis. That was B, right?

By Pennhomie33 (Pennhomie33) on Saturday, October 09, 2004 - 10:56 am: Edit

lol its me, vas.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:00 am: Edit

eek actually i'm pretty sure the absolute value one was like whenever the graph had a negative x value, it just became flipped over the x axis and therefore the entire graph became positive. the resulting thing looked kinda like a sideways lightning bolt.

OMG VASANT!! wait, i thought you took the iic already. and, i thought you were taking physics in october?

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:01 am: Edit

you can check by just graphing a random thing and then graphing abs(random thing).

By Pennhomie33 (Pennhomie33) on Saturday, October 09, 2004 - 11:05 am: Edit

lol dont worry guys, curve is so good on this, you can omit 6 and get 8 wrong and still get an 800. 50-6 = 44, minus 8*.25 = 42 raw score --> still an 800

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:07 am: Edit

AWESOME!!!!!!!!!!!!!!!!!!!!

but the ic is like one wrong = 780!! so... why are you taking it!?!? its so RISK-AY!

By Pennhomie33 (Pennhomie33) on Saturday, October 09, 2004 - 11:08 am: Edit

yeah, wang, go online.

By Jenz129 (Jenz129) on Saturday, October 09, 2004 - 11:08 am: Edit

Umm, omitting 6 AND getting 8 wrong would give you a 34 raw score, which is more like 730.

By Pennhomie33 (Pennhomie33) on Saturday, October 09, 2004 - 11:10 am: Edit

oh, whatever. i took this last year. just saying hi to my friend james wanginator!

By Pennhomie33 (Pennhomie33) on Saturday, October 09, 2004 - 11:18 am: Edit

sorry, you can omit 4, and get 3 wrong -- still 800.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:21 am: Edit

lol AWESOME!!!!

By Gostanford (Gostanford) on Saturday, October 09, 2004 - 11:23 am: Edit

what was the question for #47?

By Gostanford (Gostanford) on Saturday, October 09, 2004 - 11:23 am: Edit

what was the question for #47?

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:28 am: Edit

OH I REMEMBER!

it was that um... uh... permutation/combinatgin questin
with 8/6 senior/juniors

By Phantom (Phantom) on Saturday, October 09, 2004 - 11:29 am: Edit

Wang-for 49, I think I got 2.5? Was that the one with h=-16t^2 + 18t?

I plugged in 20 for h and did quadratic, taking the higher number.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:29 am: Edit

and where you could only pick 3/2 choices.
so it was like 8*7*6/3! times 6*5/2!

i think you can also use nrand on your calc and do it.

By Phantom (Phantom) on Saturday, October 09, 2004 - 11:30 am: Edit

Wang-I got 2002 for the combination question, but I'm really unsure about it.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:32 am: Edit

aw man you should have just graphed it. if you graphed it, the max point was at 1.5 seconds. then, at 2.5 seconds, it was at 20m. so the difference was 2.5 MINUS 1. cuz they asked time from 20m to MAX HEIGHT...

By Gostanford (Gostanford) on Saturday, October 09, 2004 - 11:32 am: Edit

yea for 47 i used nCr for both srs and jrs and multiplied together, im almost positive it was 840. and for 49 it wasnt 2.5 bc the question asked how many secs after max height, and max height was at 1.5 so it was 2.5 - 1.5 which is 1

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:34 am: Edit

uh for the combination question, if you do 8*7*6 which = the three spots available for teh 8 seniors, multiply that by the junior part which is 6*5, you get a number thats almost correct. then you have to divide that product by 3! and 2!

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:36 am: Edit

yay gostanford!
lol

By Phantom (Phantom) on Saturday, October 09, 2004 - 11:36 am: Edit

that's what they meant?? they wanted the number of seconds elapsed b/t max height and 20ft? I thought the question was asking for how much time it takes for the object to reach 20 ft on the other side of max height, which would be 2.5! Did I just read the question wrong, or was there some ambiguity I can complain about to collegeboard?

By Speeddemon608 (Speeddemon608) on Saturday, October 09, 2004 - 11:38 am: Edit

standard deviation????

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:41 am: Edit

oh that standvard devation one is definitely changed only when you multiply/divide. adding/subtracting does nothing to a st. dev value.

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:42 am: Edit

hey what did you guys get for teh one being (abs)closest to 20? i graphed it and found choice A and choice B being only hundreths away from 20....?

so i picked the closer one, B which was 6.04 i think????

By Speeddemon608 (Speeddemon608) on Saturday, October 09, 2004 - 11:43 am: Edit

crap not sure what i put, if we answered them all, how many wrong for a 800?

By Speeddemon608 (Speeddemon608) on Saturday, October 09, 2004 - 11:44 am: Edit

it said the greatest value of T, so i put 6.35(or whatever), i graphed it as well

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:44 am: Edit

like 6?

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:47 am: Edit

i graphed it too and those two answers were really close but....
are you 110% sure it said GREATEST value of t? cuz if you are, then you know what that means...

By Speeddemon608 (Speeddemon608) on Saturday, October 09, 2004 - 11:48 am: Edit

and question 49 i believe it was, which of these holds tru for a value x

sin^2(x)+cos^2(x)=2
etc etc

i plugged in numbers and none worked, so thats what i put

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:49 am: Edit

anyone remember any more random questions? or have we exhausted all the hard questoins?

By Wanginator (Wanginator) on Saturday, October 09, 2004 - 11:53 am: Edit

did you guys get a cylinder thing for the question asking all poins in space 2 away?

By Speeddemon608 (Speeddemon608) on Saturday, October 09, 2004 - 12:04 pm: Edit

yep i put cylinder of infinite height and radius 2 with line as axis

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:08 pm: Edit

Yup I got the cylinder thing.

Is the absolute graph the one that looked like a W?

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:10 pm: Edit

Oh and the trigo one with sin^2(x)+cos^2(x)=2 I thought the last two were valid because one was when sin^2 x=0 and the other cos^2 x=0..

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:10 pm: Edit

double post

By Rogerfederer (Rogerfederer) on Saturday, October 09, 2004 - 12:13 pm: Edit

For the question asking for points 2 spaces away from a line, since it stated "on a plane," shouldn't it be 2 lines parallel to the original line? Are 3D models still on a plane? Or am I just imagining that the question asked "on a plane"?

By Bifff (Bifff) on Saturday, October 09, 2004 - 12:15 pm: Edit

anybody think they know what the curve for this test is going to be?

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:16 pm: Edit

they said in space actually.... so it's 3d. or at least that's what i read....

what in the world does lateral surface area refer to? the curved side only?

By Alebed01 (Alebed01) on Saturday, October 09, 2004 - 12:17 pm: Edit

These are my answers for Math IIC

1- D
2- B
3- C
4- B
5- A
6- C
7- C
8- D
9- A
10- B
11- C
12- C
13- A
14- E
15- A
16- B
17- B
18- D
19- A
20- B
21- E
22- D
23- B
24- C
25- D
26- D
27- A
28- C
29- B
30- E
31- D
32- B
33- A
34- B
35- E
36- A
37- D
38- C
39- E
40- C
41- D
42- E
43- C
44- B
45- B
46- B
47- E
48- D
49- B
50- E

The curve is gonna be from 43-45 = 800 probably..

and yes, the answer is Cylinder...

By Ppangan (Ppangan) on Saturday, October 09, 2004 - 12:18 pm: Edit

for that trig one, sin^2(x) + cos^2(x)=2, isnt the identity sin^2(x) + cos^2(x)=1?

By Speeddemon608 (Speeddemon608) on Saturday, October 09, 2004 - 12:22 pm: Edit

yes, i dont think any of those identities were right

and 43-45 right with the rest wrong?

does anyone know the raw score-->scaled score chart? i know i got about 40 right and the rest were guesses, whats that work out to?

By Alebed01 (Alebed01) on Saturday, October 09, 2004 - 12:24 pm: Edit

it said for some number..

so the answer is B and C

By Alebed01 (Alebed01) on Saturday, October 09, 2004 - 12:24 pm: Edit

it said for some number..

so the answer is B and C

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:24 pm: Edit

what were the latter two identities for that question?

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:25 pm: Edit

yup i'm fairly certain its B and C too..

By Piman3141 (Piman3141) on Saturday, October 09, 2004 - 12:26 pm: Edit

mathIIc in June was easy. i only got 1 question wrong

By Bifff (Bifff) on Saturday, October 09, 2004 - 12:30 pm: Edit

for the absolute graph, I put the choice which only showed the curve to the right of the y-axis since the question was y=f(IxI)

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 12:33 pm: Edit

but negative values of x would result in a positive |x| so shouldnt the graph the the right bit reflected onto the left... giving a W shaped one?

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 12:34 pm: Edit

Damnit, I put sphere instead of cylinder because I didn't stop to think about the fact that it's a line, not a point, that we're getting distances from. Meh..me and my sloppiness.

Easy test, though!

By R2005 (R2005) on Saturday, October 09, 2004 - 12:44 pm: Edit

for the one where it was the absolute value of "X," i put that it was the that was reflected about the y axis. All -x values become positive, and only one graph had all positive x values.

right?

By Blee731 (Blee731) on Saturday, October 09, 2004 - 12:50 pm: Edit

I answered 45 out of 50 and omitted the rest. It was SO much easier than the Barron's tests. Geez, on the Barron's I got raw scores of mid-20's. For this one, I know I got at least a raw score of 33.

By Mjcps (Mjcps) on Saturday, October 09, 2004 - 12:55 pm: Edit

According to 2005 Sparknotes:

33=700
34=710
35=720

and so on....

minimum raw score according to 2005 sparknotes for a 800:

43

By Amrik (Amrik) on Saturday, October 09, 2004 - 12:59 pm: Edit

I think for the matrix question I narrowed it down to 5x2 and 5x4. I guessed E I think. Was that the right answer?

Some random answers:

9.4
1
II and III only
Only III causes std. dev. to change.
600-something
(3,4)
(3,0)

By Run4fun (Run4fun) on Saturday, October 09, 2004 - 12:59 pm: Edit

No, thats wrong. For the absolute value question, since it was on the inside of the function, it just eliminates all negative X-values, leaving you with choice A.

If the absolute value sign had been on the outside, then you would all be right in saying that all negative x-values are reflected over the x-axis...but that wasnt that case.

By R2005 (R2005) on Saturday, October 09, 2004 - 01:06 pm: Edit

i didn't say that.

i said that all negative "x" values become positive, so it's reflected over the Y axis (not the x-- if it were the x axis, then the absolute value sign would have surrounded f(x)).

Wasn't there only ONE graph where all x values were positive?

By Number9 (Number9) on Saturday, October 09, 2004 - 01:06 pm: Edit

I hope, r2005, thats what I put.

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 01:07 pm: Edit

R2005 is correct, an x-value cannot reflect over the x-axis.

By R2005 (R2005) on Saturday, October 09, 2004 - 01:08 pm: Edit

yeah..

i think it was c or d? something like that?

like part of a "w" tilted to the right.

By Davidrune (Davidrune) on Saturday, October 09, 2004 - 01:08 pm: Edit

I got the matrices q. wrong so far.

Here are some random stuff I remember:

- 4 + 2 root 2
- sec squared

that's all folks.

By R2005 (R2005) on Saturday, October 09, 2004 - 01:11 pm: Edit

yup.. remember that

i think it was:

2 root 2 plus 4 (same answer, just in a different arrangement).

or for the one where you had to find some value that would put you closer to 2... choice b, right?

i didn't use any identities. just plugged in random numbers.

oh.. which graph's points are only ONE point away from the origin?

eh? all of the points? (confused)

By Amrik (Amrik) on Saturday, October 09, 2004 - 01:13 pm: Edit

A circle centre (0,0) radius 1. x^2 + y^2 = 1.

Btw, when do scores come out?

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 01:15 pm: Edit

2 weeks.

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 01:19 pm: Edit

Anyone remember the answer to the question about the three equations for planes and whether or not they were parallel?

By Alebed01 (Alebed01) on Saturday, October 09, 2004 - 01:25 pm: Edit

they are all parallel and second one is between the other two..

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 01:26 pm: Edit

I said they were parallel and that 2x + 2y + 2z = 3 was in between...

By Sixsixty (Sixsixty) on Saturday, October 09, 2004 - 01:27 pm: Edit

why is it not the third one?
simplified it would be x+y+z=1.5

since the other two are x+y+z=1 and x+y+z=2

the third one should be in between should it not?

By Alebed01 (Alebed01) on Saturday, October 09, 2004 - 01:34 pm: Edit

i get the concept..
i must have mistaken #3 and #2 choices..
it has been a few hours since the test..

By Ckakalacheva (Ckakalacheva) on Saturday, October 09, 2004 - 01:37 pm: Edit

i answered that they are parallel with line L in the middle, i think

By Davidrune (Davidrune) on Saturday, October 09, 2004 - 01:41 pm: Edit

I said L was in the middle as well.

By Ckakalacheva (Ckakalacheva) on Saturday, October 09, 2004 - 01:44 pm: Edit

i put C (6,45 or something) for the "t" value of 40*e^-0,1 ....something


how about the q about the quadratic equastion with the given numbers of x and y. x=1, y=4; x=3, y=12; x=5, y=..something :o) ???

By Rogerfederer (Rogerfederer) on Saturday, October 09, 2004 - 02:00 pm: Edit

-What's the inverse of e^(x)?

-what's the 2nd term in the geometric sequence when the third term is 18 and the ratio is -3?

-What the inverse of a graph? is that when the graph is flipped over the y=x line?

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:01 pm: Edit

About the modulus of X one...

If X=-2,-1,0,1,2 ;

and corresponding vlaues of Y = 1,2,3,4,5 ;

then for |X|=2,1,0,1,2 ;
Y= 5,4,3,4,5.

Which means that the part of the graph on the POSTIVE X-axis, is reflected over to the NEGATIVE X-axis side. |X| means that there is no -ve value of |X|; BUT, the horizontal scale was marked X - NOT |X|!

Hope that made sense.

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:04 pm: Edit

-What's the inverse of e^(x)?

======ln X

-what's the 2nd term in the geometric sequence when the third term is 18 and the ratio is -3?

======= -6

-What the inverse of a graph? is that when the graph is flipped over the y=x line?

======= yes

By R2005 (R2005) on Saturday, October 09, 2004 - 02:07 pm: Edit

You confused me, Perfectdark9.

Are you referring to the same problem that I am?

Why would the absolute value of x reflect over the the NEGATIVE x-axis side? it should be the other way, regardless of how the horizontal axis was marked..

By R2005 (R2005) on Saturday, October 09, 2004 - 02:09 pm: Edit

oh, for the inverse of e^x..

there was a value for x. so it was just the natural log of that number. i think it might have been ln of 2? i can't remember.

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 02:18 pm: Edit

Yeah, the question was like if f(x) = exp(x), what's f^-1(2)?

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:25 pm: Edit

Look I'll try to explain it again...

let Y=1 when X=-1 and Y=2 when X=1.

let Y=f(X), and let another function Y=f(|X|).

lets make a table now...

X -1 1
|X| 1 1
f(X) 1 2
f(|X|) 2 2

See? When put |X| in f(X), you are essentially putting all the values for the POSTIVE X in F(X), so that the shape of the graph on the +ve xaxis is the same as that on the -ve xaxis.

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:29 pm: Edit

The thing is this: you are taking a NEGATIVE value of X, so that the graph exists at the negative side of the x-axis,

BUT,

you are putting |X| in the funtion, NOT X.

The function is f(|X|),

BUT,

the scale is marked X, NOT |X|.

X may be negative,

|X| may not be negative.

I can't explain it any clearly than that...

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:32 pm: Edit

Yeah, the question was like if f(x) = exp(x), what's f^-1(2)?

===== That basically means that, e^X = 2.

X = ln 2/ln e = ln 2

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 02:33 pm: Edit

Essentially, f(|x|) is the same thing as saying f(x) for {x:x>=0}. So, whatever the function does right of x=0, it can't exist left of x=0.

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:36 pm: Edit

^^^^^^ NO NO NO!!!

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 02:37 pm: Edit

I suppose you could look at it like that. You could also just solve it like you would finding any other inverse function:

f(x) = e^x

y = e^x

x = e^y

ln(x) = ln(e^y)

ln(x) = y

Thus

f^-1(x) = ln(x)

---
Alternatively, you could just know that the inverse of an exponential function is its logarithm

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:39 pm: Edit

Is anyone even bothering to read my explanations!?

Graph these equations,

Y = 2X + 1
Y = 2|X| + 1

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:43 pm: Edit

Graph these equations,

Y = 2X + 1
Y = 2|X| + 1

In these equations, you will have BOTH POSITVE and NEGATIVE values for X. IN BOTH EQUATIONS!

X = some negative values

|X| = some postive values equal in magnitude to X

Y = some values.

Now you plot X and Y, NOT |X| and Y!

By R2005 (R2005) on Saturday, October 09, 2004 - 02:43 pm: Edit

Ooh.. perfectdark.. I think I got it.

Just because we have the abs. value of x doesn't mean you can't PLUG IN a negative value for x. right?

So, plug in -5, per se, and end up with a positive answer.

eh?

if you can't tell already, i'm not exactly mathematically inclined..
;)

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 02:49 pm: Edit

I know what you mean perfectdark, the question is WHERE are you evaluating the absolute value.

You're right if you evaluate it as part of the definition of the function.

However, if you evaluate it BEFORE you enter the input into the function, then f(|-5|) would be the same thing as f(|5|), and you'd only be achieving y values correspondant to positive x-values.

That's what confused me.

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:51 pm: Edit

Finally, yeah!

See, when X=a and Y=b;

and when X=-a and Y=c;

if you plot y=f(|X|),

you get; when X=a, |X|=a, Y=b

when X=-a, |X|=a and Y= b again!

So what you ACTUALLY PLOT is (a,b) and (-a,b).

By Hiamerica (Hiamerica) on Saturday, October 09, 2004 - 02:52 pm: Edit

OK for the one with the avergaes for the student calulator house people things, what did you get.?

By R2005 (R2005) on Saturday, October 09, 2004 - 02:55 pm: Edit

Hiamerica..

I think I got a (perhaps b?) for that one.

i found the total # of calculators (i.e. 2 people have 6 = 12) and divided that by the total number of people.

2.4, i think?

i can't remember.

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 02:57 pm: Edit

However, if you evaluate it BEFORE you enter the input into the function, then f(|-5|) would be the same thing as f(|5|), and you'd only be achieving y values correspondant to positive x-values.


====== Again, X may be postive or negative, |X| is always positive, and you plot Y against X and not |X|.

In your example, X IS NOT |-5|;

X = -5;

|X|=|-5|=5

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 03:01 pm: Edit

Yeah it makes sense, you're right. Good thing I put that as my answer

By Hiamerica (Hiamerica) on Saturday, October 09, 2004 - 03:15 pm: Edit

Dudes, and for the card probability thing, I got 7/15. what did you guys get?

By Lolboyer (Lolboyer) on Saturday, October 09, 2004 - 03:18 pm: Edit

Nope

By Lolboyer (Lolboyer) on Saturday, October 09, 2004 - 03:19 pm: Edit

i think i got 1/15 because only values were 15, and 30 so 2/30 = 1/15

AND

so what letter choice was the answer? A , B , C , or D for the ABS value question?

By Hiamerica (Hiamerica) on Saturday, October 09, 2004 - 03:21 pm: Edit

dude, it said from 1 to 30 right, how is it 39. also it said divisible by 3 or 5.

By Lolboyer (Lolboyer) on Saturday, October 09, 2004 - 03:22 pm: Edit

divisible by 3 AND 5 it said? no? oh god i hope it didnt say OR.

By Hiamerica (Hiamerica) on Saturday, October 09, 2004 - 03:23 pm: Edit

or ya. help me out here guys! i need an answer! i am pretty sure it said OR

By Barc202 (Barc202) on Saturday, October 09, 2004 - 03:27 pm: Edit

i'm pretty sure it said either 3 or 5

By Hiamerica (Hiamerica) on Saturday, October 09, 2004 - 03:29 pm: Edit

But what answer did you get Barc202. 7/15. please say i am right

By Barc202 (Barc202) on Saturday, October 09, 2004 - 03:31 pm: Edit

yeah i got 14/30 which reduces to 7/15

By Jess13 (Jess13) on Saturday, October 09, 2004 - 03:33 pm: Edit

def said 3 OR 5.

By Gostanford (Gostanford) on Saturday, October 09, 2004 - 03:55 pm: Edit

what did ppl get for the cylinder question about lateral area and volume? like 4787 or whatever?

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 03:56 pm: Edit

Yep 7/15

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 03:59 pm: Edit

I thought it was 3 AND 5?

I put 1/15...

If it was OR, then maybe it was 7/15. Grr, I hate these tests.

-- I got something liek 4748 for the cylinder one too.

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 04:00 pm: Edit

That's right, Cognitio, for the cylinder one.


I omitted two I think, and I am guessing that I got perhaps one or two wrong?

By Succor101 (Succor101) on Saturday, October 09, 2004 - 04:08 pm: Edit

Dudes, I think the cards problem went like this:
A stack 'o cards is numbered 1 to 30 inclusive...if a card is drawn at random, what is the prob that it'll be divisible by 3 OR 5?

30/3 = 10
30/5 = 6

10+6 = 16

16/30 = 8/15

So 8/15 is actually right, if I'm not mistaken...

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 04:11 pm: Edit

Succor: You have to subtract the overlap of the ones that are divisible by both 3 and 5, which include 15 and 30.

14/30 = 7/15

By Succor101 (Succor101) on Saturday, October 09, 2004 - 04:12 pm: Edit

Huh? crap

By Scee3 (Scee3) on Saturday, October 09, 2004 - 04:14 pm: Edit

Nope. 15 and 30 are divisible by 3 AND 5, so you've got to take that into account, too.
Anyway, BLAHH, I'm so mad at myself for skipping as many as I did. Way too cautious. Geez. Left 10 blank. Hoping for a 750+...

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 04:20 pm: Edit

Doesn't 3 OR 5 imply "either but not both"?

By Cognitio (Cognitio) on Saturday, October 09, 2004 - 04:24 pm: Edit

In terms of logic, 3 or 5 implies "either or both". If you want to do "either but not both", it would be 3 xor 5.

By Perfectdark9 (Perfectdark9) on Saturday, October 09, 2004 - 04:30 pm: Edit

Nope. 15 and 30 are divisible by 3 AND 5, so you've got to take that into account, too.


====== You cannot count 15 and 30 twice.

These two numbers are in the intersection of two sets. They are members of both, but are not counted twice.

e.g. If I take French and Basketball, and you are tallying the total numnber of students in the school, you won't count me twice.

By Shaman88 (Shaman88) on Saturday, October 09, 2004 - 04:37 pm: Edit

Gostanford...

I got around 4787 because since the lateral SA = 1200pi, and height = 3r, and LA(cylinder) = 2*pi*r*h. Plugging in 2*pi*r*3r gives
6*pi*r-squared = 1200pi. Solving for r and multiplying r by three for h, and plugging back in to V = pi*r-squared*h gives you about 4787 cubic centimeters.

By Succor101 (Succor101) on Saturday, October 09, 2004 - 04:53 pm: Edit

Yah, my bad...didn't realize I had to subtract out the 2 #'s

By Chidimma (Chidimma) on Saturday, October 09, 2004 - 04:57 pm: Edit

I thought the test was super EASY. Wow, I was so scared after hearing "stories" about it. But then again, I DID study my butt off. A lot of problems on the test were similar to the problems from the sparknotes '5 More practice tests for IIC'. YAY. I'm feeling really confident about this test. I omitted 5.

By Anjin (Anjin) on Saturday, October 09, 2004 - 05:09 pm: Edit

"Hiamerica..

I think I got a (perhaps b?) for that one.

i found the total # of calculators (i.e. 2 people have 6 = 12) and divided that by the total number of people.

2.4, i think?

i can't remember. "

I got 2.48 for that one.
What did people get for question 49?

By Sakrei (Sakrei) on Saturday, October 09, 2004 - 05:12 pm: Edit

Anyone wanna talk about Math2c IM me, BbOyFoiBLe

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 05:15 pm: Edit

The calculator question was A I think. It was a tricky question by the way the graph was set up.

By Lolboyer (Lolboyer) on Saturday, October 09, 2004 - 05:26 pm: Edit

what was the answer CHOICE to the f|x| one.. was it A? pls help

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 05:42 pm: Edit

CRAP CRAP. Anyone remember that question about x^2 + y^2 = 25? Anyone remember what they put for this answer?

By Hiamerica (Hiamerica) on Saturday, October 09, 2004 - 05:45 pm: Edit

can anyone verify the calulator qstn. is it 2.48. thats what i got.

By Theapprentice (Theapprentice) on Saturday, October 09, 2004 - 05:56 pm: Edit

What was that question on the 2nd to the last page with this:

O(t) or something = 40e^(-.1T)cos2T...
yea i think thats it...
i just plugged in the middle one and it worked
after i finished i went back and i graphed... when y=20 i took the X value... right?
6.75 or something.. 6. something

By Theapprentice (Theapprentice) on Saturday, October 09, 2004 - 05:58 pm: Edit

answer on that one was A, the point was 3,4
u can either substitute in the points and it works or...
the easiest way is to just sketch a circle w. center @ origin and r=5 (x2 + y2 =r2)

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 06:40 pm: Edit

Phew, all correct thus far

By Anjin (Anjin) on Saturday, October 09, 2004 - 06:48 pm: Edit

So what is the consesus for teh card one? 14/30 (7/15)?

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 06:50 pm: Edit

It's 7/15

By Ichiboy (Ichiboy) on Saturday, October 09, 2004 - 06:55 pm: Edit

they never have had calc. on IIc. i skipped two tho. the sa/volume one was wierd. i kept getting a diff answer then the book.

By Samwise (Samwise) on Saturday, October 09, 2004 - 07:35 pm: Edit

Same here, not sure why

By Nathaxtaldar (Nathaxtaldar) on Saturday, October 09, 2004 - 08:09 pm: Edit

h=3r
SA=2pirh

Given SA=1200

1200=2pir(3r)
1200=6pir^2
r^2=63.66
r=7.98

V=pi r^2 h
V=pi r^2 (3r)
V=pi 3r^3
V=pi 3(7.98)^3
V=4787 cm^3

hopefully I did it right

I thought it was easier than June's too.. I got a 750 last time I omitted 4 on this one though

By Davidrune (Davidrune) on Saturday, October 09, 2004 - 08:16 pm: Edit

Legendofmax it was (3,4) or (4,3)

By Chidimma (Chidimma) on Saturday, October 09, 2004 - 09:46 pm: Edit

card problem: 7/15
x^2 + y^2 = 25? A, which was 5 away from the origin, i think its coordinates were (3,4)? right?

how do you solve the one with the surface area of the cylinder?
I WANT MY SCORE NOW.

By Anjin (Anjin) on Saturday, October 09, 2004 - 09:46 pm: Edit

For the inverse graph, I tihnk it was the one wqhich crossed (3,0). Anyone remember that one? For the 40e^ etc etc, i got answer choice c, it was like 6.35 or something like that.
1 second for teh difference between the max point and x=20.

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 09:50 pm: Edit

An inverse function is just the function reflected over the line y=x

By Jonnyace860 (Jonnyace860) on Saturday, October 09, 2004 - 09:55 pm: Edit

here are the answers i remember

juniors and seniors - 870
cylinder - 4400somethin
inverse of e^x is lnX
last one for the std dev
last 2 for the very last problem
infinite cylinder
-.25 +c
f(|x|) - same thing reflected to -x axis
k = 2
n = n
uhhhh.........
1 second
-6 for geometric series
7/15
2.4 or somethin for calculator problem
log problem - - (3,0)
circle - x^2+y^2 = 1 and (3,4)


any thoughts or questions?

By R2005 (R2005) on Saturday, October 09, 2004 - 10:55 pm: Edit

there was one which was something along the lines of..

4(a) + 4(b) + 4(c) + 4(e) = n
-------------------------
16, i think?

they wanted to know, in terms of n, what the average of a+b+c+e were. It was just plain "n," right?

By Legendofmax (Legendofmax) on Saturday, October 09, 2004 - 10:59 pm: Edit

Yes it is just n

By Tigeruppercut (Tigeruppercut) on Sunday, October 10, 2004 - 12:47 am: Edit

i'm taking it in december...

what are some general topics you guys could suggest me to study?

By Amrik (Amrik) on Sunday, October 10, 2004 - 09:15 am: Edit

Use the Barron's book. Some people say it's overkill, but because it's harder you will be better prepared for the test.

By Amrik (Amrik) on Sunday, October 10, 2004 - 09:19 am: Edit

I got k = -4/7

By Perfectdark9 (Perfectdark9) on Sunday, October 10, 2004 - 09:40 am: Edit

There were two different question involving k; I defenitly remember one of them being k = -4/7

By Davidrune (Davidrune) on Sunday, October 10, 2004 - 10:23 am: Edit

I got -4/7 too.

By Legendofmax (Legendofmax) on Sunday, October 10, 2004 - 10:28 am: Edit

Yep one was most def -4/7.

By Sakrei (Sakrei) on Sunday, October 10, 2004 - 10:35 am: Edit

what is 5 wrong 3 omit translate to?

By Anjin (Anjin) on Sunday, October 10, 2004 - 11:33 am: Edit

I got 1/7 for teh product of two somethings. It was an earlier question, like question 11. I think it was the product of the slopes of the lines.

By Cooldude (Cooldude) on Sunday, October 10, 2004 - 11:37 am: Edit

i think it was -1/7

By Anjin (Anjin) on Sunday, October 10, 2004 - 12:14 pm: Edit

um, well one product was poistive 1, one was -1/7, and the other was -1. So 1/7 x -1 x -1 is 1/7.

By R2005 (R2005) on Sunday, October 10, 2004 - 12:36 pm: Edit

yup. it was positive 1/7.

i'm absolutely positive (no pun intended.. mwahaha).

By Theapprentice (Theapprentice) on Sunday, October 10, 2004 - 02:11 pm: Edit

Yea i got -4/7
i dunno why but that took me like 10 mins
lol dint matter since the test took me like 40 mins
The slope thing was 1/7 i believe

but the other one like 1/a + 1/2a + 1/3a = 1/6
that was -4/7
i believe so... i check on my calculator and it worked

and anybody whos doing math2C later... USE BARRONS
barrons is such a good book.. i cursed it till i took the test... it preps u soo welll.. even tho u will wanna kill urself, its such a good feeling when u take the test... i wanted to jump up and dance on my desk lol
all the pr and kaplan ppl around me were furiously punchin away on their stupid ti-89s
oya do nOT buy a ti-89

i recommend a really easy, simple graphing calculator.. i used the casio 7400g +. It is simple, easy to program, and has functions that are super-super easy to access.

The barrons book does not teach well however... use your precalc book/trig book or whatever to study and learn. PR does a good job of teaching too.

The surface area thing was easy... its soo easy... they GIVE U THE FORMULA IF U DONT KNOW
just figure it out

the one that had abcd and the avg of them is n
a + B+ C+ D) /4 = N

By Theapprentice (Theapprentice) on Sunday, October 10, 2004 - 02:11 pm: Edit

Yea i got -4/7
i dunno why but that took me like 10 mins
lol dint matter since the test took me like 40 mins
The slope thing was 1/7 i believe

but the other one like 1/a + 1/2a + 1/3a = 1/6
that was -4/7
i believe so... i check on my calculator and it worked

and anybody whos doing math2C later... USE BARRONS
barrons is such a good book.. i cursed it till i took the test... it preps u soo welll.. even tho u will wanna kill urself, its such a good feeling when u take the test... i wanted to jump up and dance on my desk lol
all the pr and kaplan ppl around me were furiously punchin away on their stupid ti-89s
oya do nOT buy a ti-89

i recommend a really easy, simple graphing calculator.. i used the casio 7400g +. It is simple, easy to program, and has functions that are super-super easy to access.

The barrons book does not teach well however... use your precalc book/trig book or whatever to study and learn. PR does a good job of teaching too.

The surface area thing was easy... its soo easy... they GIVE U THE FORMULA IF U DONT KNOW
just figure it out

the one that had abcd and the avg of them is n
a + B+ C+ D) /4 = N

By Anjin (Anjin) on Sunday, October 10, 2004 - 02:35 pm: Edit

1/a question was 11. I pluged it into my calculator and that worked. I am absolutely positive.

By Theapprentice (Theapprentice) on Sunday, October 10, 2004 - 02:45 pm: Edit

wait
oops yea ur right
i remember now
-4/7 was something else

By Anjin (Anjin) on Sunday, October 10, 2004 - 03:00 pm: Edit

Correcto. I did get /4/7 for something else, just forgot what.

What score would be 3 omit, 5 wrong?

By Cognitio (Cognitio) on Sunday, October 10, 2004 - 03:13 pm: Edit

Anyone remember the question that was like if y = b^x, what does y/b equal?

I put y/b = b^(x-1) I think

By Davidrune (Davidrune) on Sunday, October 10, 2004 - 03:15 pm: Edit

yea... I got the same.

just multiply both sides with b.

And u get what you started with.

By Piman3141 (Piman3141) on Sunday, October 10, 2004 - 03:15 pm: Edit

you are correct. I didnt take the test, but assuming you wrote the problem right, that's the right answer.

By Davidrune (Davidrune) on Sunday, October 10, 2004 - 04:08 pm: Edit

Anybody else think of qs.

I was unsure of the point that defines a distance 2 inches away from a line.

I chose the cylinder, which I know now is right.

By Astrix (Astrix) on Sunday, October 10, 2004 - 04:30 pm: Edit

Ok, so the cylinder question, it's a question I would think would be very easy for me, but I couldn't get the answer. What am I doing wrong? It's driving me crazy, coz this is supposed to be easy.

Lateral surface area = 1200
2 pi r h = 1200
2 * pi * r * 3r = 1200
6 * pi * r^2 = 1200
r^2 = 200 / pi
r^2 = 63.69
r = 7.98

Volume = SHITTTTTTTT. NOW I GET IT

WHY THE HELL WAS I DOING R^3 for the volume?? WHAT AM I???

By Davidrune (Davidrune) on Sunday, October 10, 2004 - 04:44 pm: Edit

I got 4787 for that question. Is that right?

By Legendofmax (Legendofmax) on Sunday, October 10, 2004 - 04:49 pm: Edit

LOL "Volume = SHITTTTTTTT. NOW I GET IT" I love that answer! We should have more answers like that in our world, no?

But yes the answer to that was 4787 or something, choice C.

By Davidrune (Davidrune) on Sunday, October 10, 2004 - 04:51 pm: Edit

Alright guys, how well do you think you did in Math IIC? We can compare our predictions to reality in about 10 days.

I'm predicting 790. If that's possible.

Does anybody know what date we get our score bakc?

By Lolboyer (Lolboyer) on Sunday, October 10, 2004 - 05:19 pm: Edit

790 or 800 for me.. i think

By Sakrei (Sakrei) on Sunday, October 10, 2004 - 05:20 pm: Edit

in the 7/b one was 7^x-1 an option? Cause i think I accident put that and I meant to put b^x-1

By Cognitio (Cognitio) on Sunday, October 10, 2004 - 05:25 pm: Edit

740-780, depending, but anything over 700 will be fine with me

By R2005 (R2005) on Sunday, October 10, 2004 - 05:36 pm: Edit

i didn't get to 11 of them and probably missed a few?

what does that equal?

By Anjin (Anjin) on Sunday, October 10, 2004 - 05:47 pm: Edit

700-780.

By Erinvert (Erinvert) on Sunday, October 10, 2004 - 06:50 pm: Edit

what is the most you could omit and still get a 700?
Thanks

By Marko_4454 (Marko_4454) on Sunday, October 10, 2004 - 07:34 pm: Edit

Whats the best prep book for this test (Math IIC) ????

By Anjin (Anjin) on Sunday, October 10, 2004 - 07:38 pm: Edit

Get Barrons or Sparknotes.

By Davidrune (Davidrune) on Sunday, October 10, 2004 - 07:47 pm: Edit

If you get Barron's prepare to be scared. I wrote a practice test two nights before the test and I got 20 QUESTIONS WRONG!! I wrote another one, the night before and I got 10 QUESTIONS WRONG!!

However, on the actual test, I'm confident that I got less than five wrong.

By Collegebound123 (Collegebound123) on Sunday, October 10, 2004 - 08:14 pm: Edit

Even though I felt exhausted after studying from the Barron's book, I think it was the best test preparation.

But it did not include anything about matrices (just a little bit on determinants). Be sure to study those.

Only problem with Barrons was that it did not explain well. You might just want to go online at Sparknotes.com for explanations.

By Amrik (Amrik) on Sunday, October 10, 2004 - 10:17 pm: Edit

Barrons = overkill, but it's awesome. N.B. I took _both_ a scientific and a graphic calculator to the test. I ended up using the scientific calculator (Casio fx-991 ms) for 48 questions, and the graphic for 2. Also, the graphic calculator was only used to _verify_ the answers - not actually calculate them. Thus I conclude that bringing my Ti-89 was a waste of time.

By Tallyrand (Tallyrand) on Monday, October 11, 2004 - 01:15 am: Edit

I omitted SO many. Ten, to be exact. Eh. But I got most of the ones I did do right, I think.

Random answers:
1/7
infinately tall cylinder, radius 2
n
II and III only

The scary thing is I could have got anything from 680-770. I want my score NOW so I can know whether I need to retake IIC in November, or retake the SAT I then.

I hate Barrons. Nothing I learned from it was on the test.

By R2005 (R2005) on Monday, October 11, 2004 - 01:34 am: Edit

Barrons sucks.
What about the one where it asked about asymptotes (-2 and 1, i think)? I knew I and III had them.. I think), so I put "E" (I, II, and III). Am i wrong?

By Kyip (Kyip) on Monday, October 11, 2004 - 02:26 am: Edit

Amrik: What the hell...I took the June one, and my test proctor said I could only have one, and I could use the other one only if the one I was using ran out of batteries.

Sadly, I took the Ti83, which I bought a few weeks ago...which meant that I wasted more time finding buttons.

By Davidrune (Davidrune) on Monday, October 11, 2004 - 02:29 am: Edit

No, that question asked about zeros. If it ZEROS at those values. That means did they have a solution at those values. Therefore BECAUSE I and III had asymptotes, they were not the right answers.

The right answer was just II.

By Legendofmax (Legendofmax) on Monday, October 11, 2004 - 03:19 am: Edit

I believe that the right answer was just "I". II had a (x-2) on the bottom. The first one was the only equation that allowed for zeros on the numerator. The other choices created asymptotes.

By Anjin (Anjin) on Monday, October 11, 2004 - 11:44 am: Edit

No, I think David Rune is right. One was automatically eliminated, and one I eliminated becasue it had ANOTHER zero besdies the ones at 2,-1. I forgot whether it was I, or II though..

By Wanginator (Wanginator) on Monday, October 11, 2004 - 11:57 am: Edit

lol holy crap how do you guys still remmeber questions from the test?!?!

wow, collegeconfidential is like super popular now!

By Davidrune (Davidrune) on Monday, October 11, 2004 - 01:07 pm: Edit

It was I or II, I don't remember exactly.

I wrote the test two days ago!

By Theapprentice (Theapprentice) on Monday, October 11, 2004 - 01:52 pm: Edit

If u graph it, u can tell... i believe the answer was 2... its whatever makes the denominator 0

i only remember the easy ones... what was the ? itself.. then i can helpp

By Btbvector (Btbvector) on Monday, October 11, 2004 - 03:17 pm: Edit

It was I. II has no roots and III can be eliminated.

By Davidrune (Davidrune) on Monday, October 11, 2004 - 05:08 pm: Edit

For the question 40e^(-0.1t)cos(2t), is the answer b or c. Does anyone know that the numbers of the choices?

By Anjin (Anjin) on Monday, October 11, 2004 - 05:38 pm: Edit

I am pretty sure it was c.

By Davidrune (Davidrune) on Monday, October 11, 2004 - 06:23 pm: Edit

WHat was the answer for the equation that approached 2.

By Anjin (Anjin) on Monday, October 11, 2004 - 06:59 pm: Edit

i forgot the question. Do you remember it?

By Anjin (Anjin) on Monday, October 11, 2004 - 07:01 pm: Edit

Did anyone get 2.48 (62/25) for the calculator question?

What would 5 wrong, 3 omit be around?