Click here to go to the

By Leejwwc (Leejwwc) on Saturday, June 05, 2004 - 12:29 am: Edit |

How many millimeters of a .200 molar sodium hydroxide solution must be added to a 100-millimeter solution of .100 molar nitric acid to obtain a pH of 7.

the answer is 50.0 mL

I don't see how they arrived at this answer. If you can, please show me the steps---I greatly appreciate any help you can give me

By Wrathofgod64 (Wrathofgod64) on Saturday, June 05, 2004 - 12:52 am: Edit |

Ok, so a pH of 7 means that equivalence point has been reached in a strong acid strong base titration, and the moles of acid (HNO3) equals the moles of base (NaOH). The moles of acid is .100 mL * .100 M = .01 mol HNO3. Therefore, we set this equal to the molarity of NaOH * the unknown volume as so

.01 = .200 M * V

.01/.200 = V

V = .05 L or 50.0 mL

hope that helps

By Leejwwc (Leejwwc) on Saturday, June 05, 2004 - 07:17 am: Edit |

thank you wrathofgod64!

By Amylase (Amylase) on Sunday, June 06, 2004 - 09:10 am: Edit |

this is so darn simple, lol

Posting is currently disabled in this topic. Contact your discussion moderator for more information. |

Administrator's Control Panel -- Board Moderators Only Administer Page |