SAT 1 math last minute help





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Discus: SAT/ACT Tests and Test Preparation: June 2004 Archive: SAT 1 math last minute help
By Acethesats (Acethesats) on Friday, June 04, 2004 - 10:49 pm: Edit

This should have been posted a long time ago but my registration didn't get approved until today. Weird

Anyways

1.What is one possible value for the slope of a line passing through point (-1,1) and passing between points (1,3) and (2,3) but not containing either of them?

Can someone work this problem out and show me every step?

2.The first term of a sequence is -3 and every term after the first is 5 more than the term immediately preceding it. What is the value of the 101st term?

A 505
B 502
C 500
D 497
E 492

I know the answer to this problem but Iíd like to what is an easy and simple way to solve this problem.

Can someone work this problem out and show me every step?

I have the answer but donít know how itís solved. Iíd really appreciate your help.


3. There are 120 red marbles and 80 blue marbles in a bag that contains 200 marbles. If only blue marbles are to be added to the bag so that the probability of randomly drawing a blue marble from the bag becomes 2/3, how many blue marbles must be added to the bag?


I basically need to see how other people solve these problems, I can solve them but it usually takes up too much time on these particular questions.

Math is not my strong point as you can see thx for the help.

Thanks

By Number9 (Number9) on Friday, June 04, 2004 - 11:39 pm: Edit

bump

By Mhawk177 (Mhawk177) on Saturday, June 05, 2004 - 12:34 am: Edit

1st one.. make it (1.5,3) and then get the slope for the 2..

On the last one we know that 120 is 1/3 of all of it, since blue will be 2/3. therefore the total will be 120x3 which is 360. Blue needs to be 2/3 and that is 240. 240-80= 160. Add 160

By Optimizerdad (Optimizerdad) on Saturday, June 05, 2004 - 01:39 am: Edit

Q2. This is an arithmetic series: term#1 is -3, term#2 = -3 + (1)*5, term#3 = -3 + (2)*5, ..., term#n = -3 + (n-1)*5 .

So, term#101 = -3 + (101-1)*5 = -3 + 100*5 = -3 + 500 = 497 .

By Acethesats (Acethesats) on Saturday, June 05, 2004 - 02:32 pm: Edit

ok fresh off the SATs just to make sure I didn't miss it.

2^4002-2^4000 divided by 2^4000

By Crypto86 (Crypto86) on Saturday, June 05, 2004 - 02:36 pm: Edit

That's 3. The first expression can be broken up with the denominator under each. The right term is 1 and the left term is 2^2: 4- 1 = 3


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