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By Jared (Jared) on Friday, June 04, 2004 - 09:00 pm: Edit |

1. If P and Q are different points in a plane, the set of all points in this plane that are closer to P than to Q is:

A) the region of the plane on one side of a line B) the interior of a square C) a wedge-shaped region of the plane D) the region of the plane bounded by a parabola E) the interior of a circle

Answer: A (please explain)

2. If 6.31 (exponent m) = 3.02 (exponent n), what is the value of m/n?

A) -.32 B) .32 C) .48 D) .60 E) 1.67

Answer: D (please explain)

3. If the 20th term of an arithmetic sequence is 100 and the 40th term of the sequence is 250, what is the first term of the sequence?

A) -50 B) -42.5 C) 5 D) 42.5 E) 50

Answer: B (please explain)

4. The radius of the base of a right circular cone is 6 and the radius of a parallel cross section is 4. If the distance between the base and the cross section is 8, what is the height of the cone?

A) 11 B) 13 1/3 C) 16 D) 20 E) 24

Answer: E (please explain)

Thanks...you can answer any or all...thanks everyone for their help!

By Jared (Jared) on Friday, June 04, 2004 - 09:17 pm: Edit |

bump

By Luckystar1111 (Luckystar1111) on Friday, June 04, 2004 - 09:31 pm: Edit |

1. The set of points equidistant to P and Q form a line. Therefore, the set of points closer to P is this line, with one side (the side closer to P) shaded in.

2. 3.02^1.67=6.31. So, (3.02^1.67)=(6.31)^1. If m=1, then n=1.67. So, m/n=.6.

3. It takes 20 "jumps" to get from the 20th to 40th terms, and 20 of these "jumps" from 100 to 250. Thus, each "jump" must be 150/20, or 7.5. The first term of the sequence is 19 terms away from the 20th term. 19*7.5=142.5. Take 142.5 away from the 20th term(100), and this gives you -42.5.

4. The parallel cross section is in proportion to the original right circular cone. So set up the proportion: base of original/height of original=base of cross section/height of cross section. This gives you 6/8+x=4/x. Solving for x gives you 16, so the height of the orginal cone is 16=x, or 24.

Hopes this helps, and good luck tomorrow. I am also taking IIC!

By Jared (Jared) on Friday, June 04, 2004 - 10:08 pm: Edit |

Thanks a lot! good luck too!

By Mr_Sanguine (Mr_Sanguine) on Friday, June 04, 2004 - 10:11 pm: Edit |

What exactly is meant by "cross section"?

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