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By Satchamp (Satchamp) on Friday, June 04, 2004 - 02:26 pm: Edit |

http://www.sparknotes.com/testprep/books/sat2/math2c/chapter10section9.rhtml

can u explain #6?? i really dont get it.

By Optimizerdad (Optimizerdad) on Friday, June 04, 2004 - 02:41 pm: Edit |

Take it in steps. If f(-x) = f(x), then f(-x) would need to be a 'mirror image' of f(x), with the y-axis acting as the 'mirror'

e.g. f(x) = 5x if x >=0,

5 * (-x) otherwise

Now take it one step further. If f(-x)=-f(x), then for negative values of x, we would first need to use the y-axis as the 'mirror' to create f(-x)=f(x), then use the x-axis as the second 'mirror' to make f(-x) = -f(x)

e.g. f(x) = 5x if x >= 0

-5*(-x) otherwise

However, none of the functions shown seems to satisfy this requirement, unless the intersection of the x- and y-axes is not at (0,0) .

By Kewlkiwi102 (Kewlkiwi102) on Friday, June 04, 2004 - 04:17 pm: Edit |

Yeah, none of those functions are actually odd, and none satisft their requierment. And I think 3 of them arent even functions.

Get barrons my friend.

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