|By Akaflex (Akaflex) on Monday, May 17, 2004 - 03:49 pm: Edit|
can sum1 solve dis step by step
A child and his father blow up balloons together for a party. The child inflates two balloons for every three done by his father. How many balloons are inflated by each person to total 80?
how do i put two baloons for every 3 in algebra form again i juss got confuised
|By Haithman (Haithman) on Monday, May 17, 2004 - 10:30 pm: Edit|
Ok so the child blows two balloons for every three his father blows.
We dont know how many his father blows so we can say that the child blows (2/3)x or 2/3 of what his father blows.
So to total 80, we need how many the father blows (x), and how many the child blows (2/3x)
so we set up... x+(2/3)x = 80. So (5/3)x = 80. Multiply both sides by 3 3(5/3)x = (80)3 and we get 5x=240. Divide both sides by 5 (5x)/5 = (240)/x so x = 48. Now that is how many the father blew since we denoted x to equal how many the father blew. To find how many the son blew, we just simply subtract the fathers from the total (80-48) which equals how many the son blew, or 32. Or plug the x (48) into (2/3) x and you will get the same answer of 32. It works so its done.
I presume this is an SAT question?
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