Another Calc problem if people are willing!

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Discus: SAT/ACT Tests and Test Preparation: May 2004 Archive: Another Calc problem if people are willing!
By Cantwait4colleg (Cantwait4colleg) on Monday, May 10, 2004 - 11:17 pm: Edit

THANKS SO MUCH FOR THE HELP WITH THAT LAST QUESTION. THAT'S THE ANSWER I GOT...BUT I WANTED TO MAKE SURE I WAS DOING IT RIGHT. It's great to use this board when you can't get ahold of any of your friends to help you!

here is another problem:

f(x)=1 + xy = e^xy

I think i am having problems with deriving e^xy implicitly. Could someone do it and show his work. THANKS.

By Ubercollegeman (Ubercollegeman) on Monday, May 10, 2004 - 11:37 pm: Edit

f(x) = 1 + xy = e^xy

^That does not make sense.

Anyway, if you want to differentiate e^(xy) with respect to x, use the following rule:

d/dx(e^u) = e^u(du/dx)

so you know it's e^xy * d/dx(xy) =

e^xy * (x(dy/dx) + y)

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