|By Eagles122 (Eagles122) on Wednesday, March 31, 2004 - 07:58 pm: Edit|
im given the equation : f(x) = sin(cos(2x))-1
i need to find the domain and range of this function
|By Gmf05 (Gmf05) on Wednesday, March 31, 2004 - 08:18 pm: Edit|
Well you know you can take the sin and cos of any number so the domain is all reals (if it were sec csc there'd be a problem...but it's not.) Anyway, since you know it'll be oscillating it'll have the same min/max all over the place, which it will reach when sin/cos = 1, 0 or -1...Just try values and see where it hits max/min. Then, you know it'll hit those two numbers and all of those in between and that's your range. That's the simplest way to explain it.
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