|By Bluebaron1616 (Bluebaron1616) on Thursday, October 30, 2003 - 07:57 pm: Edit|
This is weird:
"Find the equation of the line tangent to equation e^x and passes through the origin."
How would you do that algebraically without a calculator?
do you have to do y=(e^x)*x and then try to find the intercept?
|By Bluebaron1616 (Bluebaron1616) on Thursday, October 30, 2003 - 07:59 pm: Edit|
oh never find, stupid me, I figured it out.
so slope is e
so equation is y=ex.
|By Miseryxsignals (Miseryxsignals) on Thursday, October 30, 2003 - 10:40 pm: Edit|
the equation for the slope of y = e^x at ANY point (derivative) is y = e^x
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