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By Bluebaron1616 (Bluebaron1616) on Thursday, October 30, 2003 - 07:57 pm: Edit |

This is weird:

"Find the equation of the line tangent to equation e^x and passes through the origin."

How would you do that algebraically without a calculator?

do you have to do y=(e^x)*x and then try to find the intercept?

By Bluebaron1616 (Bluebaron1616) on Thursday, October 30, 2003 - 07:59 pm: Edit |

oh never find, stupid me, I figured it out.

x*e^x=e^x

x=1

so slope is e

so equation is y=ex.

By Miseryxsignals (Miseryxsignals) on Thursday, October 30, 2003 - 10:40 pm: Edit |

the equation for the slope of y = e^x at ANY point (derivative) is y = e^x

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