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ok I am trying to write a program that converts roman numerals into arabic numbers, this is what i have so far.

however when i compile this to see if it is error free it doesn't work it gives me the error msgs of.

-------------------Configuration: C8P8 - Win32 Debug-------------------- Compiling... C8p8.cpp C:\Program Files\Microsoft Visual Studio\MyProjects\C8P8\C8p8.cpp(14) : error C2440: 'initializing' : cannot convert from 'char' to 'char []'

There are no conversions to array types, although there are conversions to references or pointers to arrays C:\Program Files\Microsoft Visual Studio\MyProjects\C8P8\C8p8.cpp(23) : error C2664: 'strcpy' : cannot convert parameter 2 from 'char' to 'const char *'

Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast

C:\Program Files\Microsoft Visual Studio\MyProjects\C8P8\C8p8.cpp(25) : error C2143: syntax error : missing ';' before 'switch'

C:\Program Files\Microsoft Visual Studio\MyProjects\C8P8\C8p8.cpp(26) : error C2450: switch expression of type 'char []' is illegal

Integral expression required Error executing cl.exe.

C8P8.exe - 4 error(s), 0 warning(s)

this is what i have so far with these errors

int main() {

char RomNum[100];

cout <<"enter a roman numeral" << endl;

cin.get(RomNum, 100);

cin.ignore(120, '\n'); char digit[10];

char digit2[10];

char digit3[10];

char digit4[10];

char digit5[10]; int arabic;

cout <<"enter a roman numeral" << endl;

cin.get(RomNum, 100);

cin.ignore(120, '\n');

strcpy(digit, RomNum[0])

switch(digit)

{

case 'I':

arabic = 1;

break;

}

cout << arabic << endl; return 0;

the one im particularly puzzled by is why i can't initial the char with the array

for example

i declare

char xx[] = romNum[1];

this give me an error

the general idea of this program is

eneral idea of this program is to char digit //declare this

RomNum = XXX //example of a char array

digit = RomNum[0] //basically break up the array into letters and store them into digit

switch (digit)

case "X" = 10

if (digit1 < digit2) digit 1 = -digit1

cout digit1

By Mazzo (Mazzo) on Friday, October 24, 2003 - 11:23 pm: Edit

c++. are you in AP comp sci? i thought it was java now.

im in an honors c++ class but its a joke. i have very little idea what the code above means

By Andrew123s (Andrew123s) on Saturday, October 25, 2003 - 12:00 am: Edit

Are you including string.h?

Also, as the compiler says, you can't do switch(digit) because digit is an array.

As for char xx[] = romNum[1], why are you setting an entire array to one value?

By Nekkid_Eye (Nekkid_Eye) on Saturday, October 25, 2003 - 08:42 am: Edit

thanks i screwed up shouldn't be initializing a char array into another array can only initialize one char

By Chobo (Chobo) on Saturday, October 25, 2003 - 11:48 am: Edit

Um not to be mean or anything... but the coding here is much too long and useless for a simple program to convernt Roman into arabic.