Can anyone balance this equation?





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Discus: SAT/ACT Tests and Test Preparation: October 2003 Archive: Can anyone balance this equation?
By Desigothic (Desigothic) on Thursday, October 16, 2003 - 09:28 pm: Edit

CuSO4*5H2O + Fe = FeSO4*7H2O + Cu

By Jm405 (Jm405) on Thursday, October 16, 2003 - 09:53 pm: Edit

redox!

By Desigothic (Desigothic) on Thursday, October 16, 2003 - 10:32 pm: Edit

what?

By Desigothic (Desigothic) on Thursday, October 16, 2003 - 10:33 pm: Edit

doesnt anyone know? this is so pathetic. i thought there wud be a good amount of people here who took or take ap chemistry.

By Encomium (Encomium) on Thursday, October 16, 2003 - 10:55 pm: Edit

this is interesting
i'm in apchem
we're doing redox balancing and such

the thing that's tricky here is the water....

cu2+ +2e- ->cu
fe ---fe 2+ +2e-

the electrongs are alanced.....

i don't get it sorry

By Desigothic (Desigothic) on Thursday, October 16, 2003 - 11:10 pm: Edit

it's alright. people, i have something in mind but not sure if it's even right.
in the equation, on ledt side, can i just multiply the coefficient of 5 by 7 and on the right side, can i just multiple the coefficient of 7 by 5 for water? can this be done? if it is then it's really easy to balance this equation.

By Mitodnaman (Mitodnaman) on Thursday, October 16, 2003 - 11:17 pm: Edit

this is not possible, i think. It is not about the water, but about the SO4. See, if you multiple the CuSO4*5H20 by 7, and FeSO4*H2O by 5, you get perfect balance of water and ever thing in a few more steps, but SO4 will be 7 on the reactant side and 5 on the product side, which is not at all balanced....ah, still need to think about this.

By Jm405 (Jm405) on Thursday, October 16, 2003 - 11:21 pm: Edit

CuSO4*5H2O + 2e- = Cu
Fe = FeSO4*7H2O + 2e-

since non H and O elements are balanced, balance H and O by adding H+ and H20's

so add 5 h20 to right for first half-reaction with Cu and 7 waters to the left side for the Fe half-reaction

CuSO4*5H2O + 2e- = Cu + 5h20
Fe + 7H20 = FeSO4*7H2O + 2e-

then add

CuSO4*5H2O + Fe + 2h20 = Cu + FeSO4*7H2O

By Mlsmateo (Mlsmateo) on Friday, October 17, 2003 - 01:14 am: Edit

I don't like hydrates.

By Desigothic (Desigothic) on Friday, October 17, 2003 - 06:00 am: Edit

thanx a lot jm405. i hope what you said was right.


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