Click here to go to the

By Akaflex (Akaflex) on Friday, October 10, 2003 - 03:43 pm: Edit |

A club is buying boxes of candy bars to sell for a fundraiser. If each box contains c candy bars, and each member sells x bars each day, how many boses are needed to supply enough candy bars for 3c members to sell for 5 days?

A- 15c^2x

B- x/15

C- 3x/5

D- 15c^2/x

E- 15x

Can someone plz BREAK IT DOWN so i can understand it and explain thanks

By Akaflex (Akaflex) on Friday, October 10, 2003 - 03:48 pm: Edit |

hERES ANOTHER

When n is a positive odd integer, the sum of all integers from 2 to n can be expressed as k(n+2), where the value of k depends on the value of n.

Col A.

The value of k when n is 75

Col B.

38

By 9331 (9331) on Friday, October 10, 2003 - 04:02 pm: Edit |

1. 15x

1 box has c bars

each member sells x bars

(#of members * # of bars each member sells a day * 5days) / c = # of boxes needed for 5 days

(3c * x * 5)/c=15x

2. B

from 2 to 75, there's 74 numbers

the sum from 2 to 75 is

(75 + 2) * 74 /2 = k(75 + 2)

k = 27

38 is greater

By Akaflex (Akaflex) on Friday, October 10, 2003 - 04:12 pm: Edit |

for the candy one the answer is D

By Stanfordhopeful (Stanfordhopeful) on Friday, October 10, 2003 - 04:18 pm: Edit |

I just dont see how the candy one is D... logic points to E...

By Akaflex (Akaflex) on Friday, October 10, 2003 - 04:22 pm: Edit |

ur right im sorry, but ur explanation is confusing can u tell me why u did those things. Like explain ur logic if u can

By Stanfordhopeful (Stanfordhopeful) on Friday, October 10, 2003 - 04:25 pm: Edit |

I can explain it.. I think

Look at it this way. # of candies PER box = c

# of candies sold PER day PER member = x

# of members = 3c

Candies sold by all members per day = 3cx

Candies sold by all members over 5 days = 15cx

total candies sold = 15cx

# of boxes = total candies sold/# of candies PER box = 15cx/c = 15x

By 9331 (9331) on Friday, October 10, 2003 - 04:30 pm: Edit |

To find the number of boxes needed for 5 days, first find the number of bars that will be sold.

Given: each student sells x bars per day. if they sell candy for 5 days, each will be able to sell 5*x bars

Since we have 3*c students, the total amount of candy sold in 5 days = 3*c * 5*x

Divide the total bars over c (# of bars per box) to find how many boxes are needed

15 * c* x/ c = 15x

i hope its clear now

Posting is currently disabled in this topic. Contact your discussion moderator for more information. |

Administrator's Control Panel -- Board Moderators Only Administer Page |