Confusing mATH?

Discus: SAT/ACT Tests and Test Preparation: October 2003 Archive: Confusing mATH?
 By Akaflex (Akaflex) on Friday, October 10, 2003 - 03:43 pm: Edit

A club is buying boxes of candy bars to sell for a fundraiser. If each box contains c candy bars, and each member sells x bars each day, how many boses are needed to supply enough candy bars for 3c members to sell for 5 days?

A- 15c^2x
B- x/15
C- 3x/5
D- 15c^2/x
E- 15x

Can someone plz BREAK IT DOWN so i can understand it and explain thanks

 By Akaflex (Akaflex) on Friday, October 10, 2003 - 03:48 pm: Edit

hERES ANOTHER

When n is a positive odd integer, the sum of all integers from 2 to n can be expressed as k(n+2), where the value of k depends on the value of n.

Col A.

The value of k when n is 75

Col B.

38

 By 9331 (9331) on Friday, October 10, 2003 - 04:02 pm: Edit

1. 15x
1 box has c bars
each member sells x bars

(#of members * # of bars each member sells a day * 5days) / c = # of boxes needed for 5 days
(3c * x * 5)/c=15x

2. B

from 2 to 75, there's 74 numbers
the sum from 2 to 75 is
(75 + 2) * 74 /2 = k(75 + 2)
k = 27
38 is greater

 By Akaflex (Akaflex) on Friday, October 10, 2003 - 04:12 pm: Edit

for the candy one the answer is D

 By Stanfordhopeful (Stanfordhopeful) on Friday, October 10, 2003 - 04:18 pm: Edit

I just dont see how the candy one is D... logic points to E...

 By Akaflex (Akaflex) on Friday, October 10, 2003 - 04:22 pm: Edit

ur right im sorry, but ur explanation is confusing can u tell me why u did those things. Like explain ur logic if u can

 By Stanfordhopeful (Stanfordhopeful) on Friday, October 10, 2003 - 04:25 pm: Edit

I can explain it.. I think

Look at it this way. # of candies PER box = c
# of candies sold PER day PER member = x
# of members = 3c
Candies sold by all members per day = 3cx
Candies sold by all members over 5 days = 15cx
total candies sold = 15cx

# of boxes = total candies sold/# of candies PER box = 15cx/c = 15x

 By 9331 (9331) on Friday, October 10, 2003 - 04:30 pm: Edit

To find the number of boxes needed for 5 days, first find the number of bars that will be sold.
Given: each student sells x bars per day. if they sell candy for 5 days, each will be able to sell 5*x bars
Since we have 3*c students, the total amount of candy sold in 5 days = 3*c * 5*x
Divide the total bars over c (# of bars per box) to find how many boxes are needed

15 * c* x/ c = 15x
i hope its clear now