| By Akaflex (Akaflex) on Monday, October 06, 2003 - 02:34 pm: Edit |
If n and k are integers greater than 1, then n^20 must be greater than k^60 when n is equal to which of the following?
A- k^4
B- k^3
C- 4k
D- 3k
E- k + 41
| By Sup4 (Sup4) on Monday, October 06, 2003 - 02:58 pm: Edit |
say a
(k^4)^20
k^80
| By Akaflex (Akaflex) on Monday, October 06, 2003 - 03:37 pm: Edit |
a little more explanation plz i dun understand wut ur doing
| By 9331 (9331) on Monday, October 06, 2003 - 06:03 pm: Edit |
A
n^20 > k^60
n^20 > k^(3*20)
n > k^3
B is not the answer b/c when n = k^3, n^20 = k^60.
k^4 > k^3
n = k^4 works
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