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It's a QC question..

S ={1,2,3,4,5,6}
T ={1,2,3,4,5,6}

A number is to be chosen at random from set S,and then a number is to be chosen at random from set T.

[A] The probability that the num chosen from S will be 5

[B] The probability that the sum of the 2 numbers chosen will be 7 that the num

By Mo222 (Mo222) on Sunday, October 05, 2003 - 01:18 pm: Edit

B

By Joeybg (Joeybg) on Sunday, October 05, 2003 - 01:24 pm: Edit

nope
BTW ignore "that the num" in the problem

By Doofus (Doofus) on Sunday, October 05, 2003 - 01:33 pm: Edit

C..

1/6

6(1/36)=1/6

Ballin in tha mix

By Xiggi (Xiggi) on Sunday, October 05, 2003 - 01:34 pm: Edit

LOL = This was asked yesterday.

Answer is C. A (First set) is 1/6 and second is 6/36 or 1/6.

Check details in yesterday's post.