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By Mitodnaman (Mitodnaman) on Saturday, October 04, 2003 - 03:54 pm: Edit |

this is level 5. I got all number 5 Math questions except this.

If k is a positive integer, which of the following must represent an even integer that is twice the value of an odd integer?

a) 2k

b) 2k+3

c) 2k+4

d) 4k+1

e) 4k+2

what in the world is the question asking? Will be much obliged for an answer.

By Akaflex (Akaflex) on Saturday, October 04, 2003 - 03:58 pm: Edit |

is the answer E? if it is ill explain but if no...

By Fairyofwind (Fairyofwind) on Saturday, October 04, 2003 - 04:08 pm: Edit |

Yes. E=4k+2=2(2k+1). Done.

By Firebird12637 (Firebird12637) on Saturday, October 04, 2003 - 06:07 pm: Edit |

2k + 1 is always one more than an even integer, thus, its odd, multiply it by two and get 4k+2

By Z00b (Z00b) on Saturday, October 04, 2003 - 06:22 pm: Edit |

Yes, on these even/odd problems, it's good to remember/relearn the basic rules dealing with even/odd numbers, unless you can easily come up with them on your own. 2x is always even, 2x+1 is always odd, odd + odd = even, odd * odd=odd etc.

By Mitodnaman (Mitodnaman) on Saturday, October 04, 2003 - 08:54 pm: Edit |

thanks every one:

the wording kind of confused me.

the answer is E.

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