|By Mitodnaman (Mitodnaman) on Saturday, October 04, 2003 - 03:54 pm: Edit|
this is level 5. I got all number 5 Math questions except this.
If k is a positive integer, which of the following must represent an even integer that is twice the value of an odd integer?
what in the world is the question asking? Will be much obliged for an answer.
|By Akaflex (Akaflex) on Saturday, October 04, 2003 - 03:58 pm: Edit|
is the answer E? if it is ill explain but if no...
|By Fairyofwind (Fairyofwind) on Saturday, October 04, 2003 - 04:08 pm: Edit|
Yes. E=4k+2=2(2k+1). Done.
|By Firebird12637 (Firebird12637) on Saturday, October 04, 2003 - 06:07 pm: Edit|
2k + 1 is always one more than an even integer, thus, its odd, multiply it by two and get 4k+2
|By Z00b (Z00b) on Saturday, October 04, 2003 - 06:22 pm: Edit|
Yes, on these even/odd problems, it's good to remember/relearn the basic rules dealing with even/odd numbers, unless you can easily come up with them on your own. 2x is always even, 2x+1 is always odd, odd + odd = even, odd * odd=odd etc.
|By Mitodnaman (Mitodnaman) on Saturday, October 04, 2003 - 08:54 pm: Edit|
thanks every one:
the wording kind of confused me.
the answer is E.
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