|By Parhelia (Parhelia) on Thursday, May 01, 2003 - 09:44 pm: Edit|
to see the 2001 Calc AB free response section. Go to question (1) and do part (c)
I want to see if my answer is correct (7.292 units^3).
|By Heatwave345 (Heatwave345) on Thursday, May 01, 2003 - 09:58 pm: Edit|
ummm... i got 8.332
i used the "disk" method and ended up with:
pi*integral(((2-x^3)^2-(tan(x))^2)dx) from 0 to 0.902
0.902 is the intersection of the two functions.
plugging that into the calculator yields 8.332 units^3
|By Parhelia (Parhelia) on Thursday, May 01, 2003 - 10:22 pm: Edit|
Heatwave, you're correct, the answer is 8.332 units^3. I see what I did wrong.
|By Parhelia (Parhelia) on Sunday, May 04, 2003 - 07:45 pm: Edit|
I have another calc question.
and do number (5). These are my (probably wrong) answers:
a) 125pi/12 cm^3
b) -15pi/8 cm^3/hr
c) could someone explain this? Is the constant of proportionality equal to -3/10?
|By Brd (Brd) on Sunday, May 04, 2003 - 08:26 pm: Edit|
All your answers are correct. To show part c), you just have to show that
A = pi r^2 = (1/4) pi h^2
dV/dt = -(3/40) pi h^2
dV/dt = -(3/10) [(1/4) pi h^2] = -3/10 A
and you are done.
|By Parhelia (Parhelia) on Sunday, May 04, 2003 - 08:36 pm: Edit|
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